In what case is the distance covered in the first second in uniformly accelerated motion not numerically

In what case is the distance covered in the first second in uniformly accelerated motion not numerically equal to half the acceleration?

For uniformly accelerated movement, the following formula is valid, which expresses the displacement of the body: S = V0 * t + a * t ^ 2/2, where V0 is the initial speed of movement, t is the time of movement, a is the acceleration of movement.
When the initial speed of movement is V0 = 0, then the formula will look like: S = a * t ^ 2/2.
For t = 1 s, S = a / 2.
In order for the traversed path S not to be equal to a / 2 at t = 1 s, it is necessary that the initial speed is not equal to 0.