In what liquid was the body lowered, if the volume of the body is 200 cm3 and a buoyant force of 160N acts on it.

Given:

Farchimedes = 160 Newton – buoyancy force acting on a body immersed in a liquid;

g = 10 meters per second squared – gravitational acceleration;

V = 200 cubic centimeters = 0.0002 cubic meters – the volume of a body immersed in a liquid.

It is required to determine in which liquid the body is immersed.

Let’s find the density of the liquid into which the body was immersed:

Farchimedes = V * g * ro, hence:

ro = Farchimedes / (V * g) = 160 / (0.0002 * 10) = 160 / 0.002 = 80,000 kg / m3.

Answer: the body is immersed in a liquid with a density equal to 80,000 kg / m3.

Note: in nature, there is no liquid with such a density. Most likely, it has an error in the condition of the problem (for example, the buoyancy force or the volume of the body is not indicated correctly), but the solution to the problem itself is correct.