In what medium is a charge of 3.2 * 10 ^ -8 C placed, if at a distance of 6 cm from it the electric

In what medium is a charge of 3.2 * 10 ^ -8 C placed, if at a distance of 6 cm from it the electric field strength is 4 * 10 ^ 4 N / C?

Data: q (charge placed in an unknown medium) = 3.2 * 10 ^ -8 C; r (distance from the charge) = 6 cm (0.06 m); E (electric field strength) = 4 * 10 ^ 4 N / C.

Reference values: ε0 (electrical constant) = 8.85 * 10 ^ -12 F / m.

The medium in which the charge was placed is determined by its dielectric constant: E = q / (4 * Π * ε * ε0 * r ^ 2), whence ε = q / (E * 4 * Π * ε0 * r ^ 2 ).

Calculation: ε = 3.2 * 10 ^ -8 / (4 * 10 ^ 4 * 4 * 3.14 * 8.85 * 10 ^ -12 * 0.06 ^ 2) = 2 (the charge was placed in gasoline) …