In what volume of water is it necessary to dissolve the hydrogen chloride formed by weak heating of 234 grams

In what volume of water is it necessary to dissolve the hydrogen chloride formed by weak heating of 234 grams of sodium chloride with a concentrated solution of sulfuric acid to obtain a 20 percent solution of hydrochloric acid.

Given:
m (NaCl) = 234 g
ω (HCl) = 20%

To find:
V (H2O) -?

Decision:
1) Write the reaction equation:
NaCl + H2SO4 = (30-50C) => NaHSO4 + HCl ↑;

2) Find the amount of NaCl substance:
n (NaCl) = m (NaCl) / Mr (NaCl) = 234 / 58.5 = 4 mol;

3) Find the amount of HCl substance (taking into account the reaction equation):
n (HCl) = n (NaCl) = 4 mol;

4) Find the mass of HCl:
m (HCl) = n (HCl) * Mr (HCl) = 4 * 36.5 = 146 g;

5) Find the mass of the HCl solution:
m solution (HCl) = m (HCl) * 100% / ω (HCl) = 146 * 100% / 20% = 730 g;

6) Find the mass of H2O in this solution:
m (H2O) = m solution (HCl) – m (HCl) = 730 – 146 = 584 g;

7) Find the volume of H2O:
V (H2O) = m (H2O) / ρ (H2O) = 584/1 = 584 ml.

Answer: The volume of H2O is 584 ml.