In what volume of water is it necessary to dissolve zinc sulfate heptahydrate weighing

In what volume of water is it necessary to dissolve zinc sulfate heptahydrate weighing 100 g to obtain a solution with w znso4 = 0.01.

Let’s find the mass of zinc sulfate in 100 g of heptahydrate:
Mr (ZnSO4 * 7H2O) = 287 g / mol;

Mr (ZnSO4) = 161 g / mol;

m (ZnSO4) = 161/287 * 100 = 56.1 g.

Let’s find the mass of the solution to be obtained:
m (p-pa) = m (ZnSO4) / ω (ZnSO4) = 56.1 / 0.01 = 5610 g.

Let’s find the volume of water:
m (H2O) = m (p-pa) – m (ZnSO4) = 5610 – 56.1 = 5553.9 g;

The density of water is 1 g / ml, therefore, this mass of water occupies a volume of 5553.9 ml or 5.5539 liters.

Answer: 5.5539 liters.