In what wavelength range does the receiver operate if the capacitance of its oscillatory circuit
May 18, 2021 | education
| In what wavelength range does the receiver operate if the capacitance of its oscillatory circuit can be changed from 60 to 240 pF, and the inductance is 50 μH?
Given:
C1 = 60pF = 6 * 10 ^ -11F,
C2 = 240pF = 2.4 * 10 ^ -10F,
L = 50μH = 5 * 10 ^ -5H,
s = 3 * 10 ^ 8m / s.
Decision:
The wavelength will be:
λ = C / f, where λ is the wavelength in meters, C is the capacitance in farads and f is the frequency in hertz;
f = 1 / (2π√LC) = C / λ, where L is the inductance in henry;
λ = 2πs√LC;
λ1 = 2 * 3.14 * 3 * 10 ^ 8m / s * √ (5 * 10 ^ -5Hn * 6 * 10 ^ -11F) = 103m;
λ2 = 2 * 3.14 * 3 * 10 ^ 8m / s * √ (5 * 10 ^ -5H * 2.4 * 10 ^ -10F) = 206.5m.
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