In which case and how many times was the great work done by electric forces: when transferring a charge of 150

In which case and how many times was the great work done by electric forces: when transferring a charge of 150 C or when transferring a charge of 180 C? In both cases, the voltage across the sections of the circuit was 4.5 V.

q1 = 150 Cl.

q2 = 180 Cl.

U = 4.5 V.

A2 / A1 -?

When the charge moves, the work of electrostatic forces A is determined by the formula: A = q * U, where q is the magnitude of the electric charge, U is the voltage between the points of movement of the charge.

A1 = q1 * U.

A1 = 150 Cl * 4.5 V = 675 J.

A2 = q2 * U.

A2 = 180 Cl * 4.5 V = 810 J.

A2 / A1 = 810 J / 675 J = 1.2.

Answer: the work of electrostatic forces when transferring an electric charge q2 = 180 C is 1.2 times more than when transferring a charge q1 = 150 C.