In which case is more hydrogen produced when zinc, weighing 15 g, is reacted with sulfuric acid or selenic acid?

Zinc dissolves in sulfuric acid, the reaction proceeds according to the following chemical equation:

Zn + H2SO4 = ZnSO4 + H2;

Zinc dissolves in hydrochloric acid, the reaction is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Thus, the amount of hydrogen evolved is independent of the acid. When the same amount of zinc reacts with sulfuric and hydrochloric acid, the same amount of hydrogen will be released. Let’s calculate the volume of hydrogen.

Let’s find the chemical amount of zinc. For this purpose, we divide its weight by the molar weight of elemental zinc.

M Zn = 65 grams / mol;

N Zn = 15/65 = 0.231 mol;

The same amount of hydrogen will be released.

Let’s define its volume.

To do this, we multiply the amount of substance by the volume of 1 mole of gas (filling the space with 22.4 liters).

V H2 = 0.231 x 22.4 = 5.17 liters;