In which case more water is formed a) when hydrogen is reduced with 10 g of copper oxide1
In which case more water is formed a) when hydrogen is reduced with 10 g of copper oxide1 b) when hydrogen is reduced with 10 g of copper oxide2.
1. Find the amount of copper oxide substance (I).
2. We make the equation of the reaction between hydrogen and copper oxide (I).
We find the quantitative ratios of copper oxide and water according to the reaction equation (1 mol of oxide and 1 mol of water, that is, they react 1: 1).
3. Let’s calculate the mass of water.
4. Find the amount of copper (II) oxide substance.
5. We compose the reaction equation, find the quantitative ratio of water oxide (1: 1).
The amount of oxide and water is the same.
6. Find the mass of water.
7. Compare the obtained masses of water in each case: the mass of water turned out to be larger when reducing copper (II) oxide with hydrogen.