In which case will the volume of the resulting hydrogen be greater: when 11.2 g of iron interacts

In which case will the volume of the resulting hydrogen be greater: when 11.2 g of iron interacts with an excess of sulfuric acid solution or when 13 g of zinc interacts with an excess of hydrochloric acid?

Iron reacts with sulfuric acid to form ferrous sulfate and generate hydrogen.

Fe + H2SO4 = FeSO4 + H2;

M Fe = 56 grams / mol;

N Fe = 11.2 / 56 = 0.2 mol;

Thus, with 0.2 mol of iron, 0.2 mol of hydrogen can be obtained.

The same volume of hydrogen can be synthesized with zinc and hydrochloric acid.

Zinc reacts with hydrochloric acid according to the following scheme:

Zn + 2HCl → ZnCl2 + H2;

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

Since the amounts of metals and hydrogen in the two options are equal, an equal amount of gas will be obtained.

The volumes of hydrogen in the two versions are equal and amount to 0.2 mol x 22.4 = 4.48 liters;