Let’s calculate the mass fraction of aluminum in cryolite:
Mr (Na3AlF6) = 23 * 3 + 27 + 6 * 19 = 210 g / mol;
ω (Al) = 27/210 = 0.129;
Let’s calculate the mass fraction of aluminum in the aluminate:
Mr (NaAlO2) = 23 + 27 + 16 * 2 = 82 g / mol;
ω (Al) = 27/82 = 0.329;
Answer: the mass fraction of aluminum is greater in sodium aluminate.
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