In which of the reactions hydrogen acts as an oxidizing agent: a) Н2 + Сl2 → 2HCl

| August 1, 2021 | education

In which of the reactions hydrogen acts as an oxidizing agent: a) Н2 + Сl2 → 2HCl c) Н2 + S → Н2S b) Н2 + СгО → Сu + Н2O d) 2Na + Н2 → 2NaH

a) H2 + Cl2 → 2HCl.

We arrange the oxidation states.

H2 (0) + Сl2 (0) → 2H (+) Cl (-).

H2 (0) -2e = 2H (+) – Reducing agent (Oxidation process).

Сl2 (0) + 2е = 2Cl (-) – Oxidizing agent (Reduction process).

c) H2 + S → H2S.

We arrange the oxidation states.

H2 (0) + S (0) → H2 (+) S (2-).

H2 (0) -2e = 2H (+) – Reducing agent (Oxidation process).

S (0) + 2e = S (2-) – Oxidant (Reduction process).

b) Н2 + СгО → Сu + Н2O.

We arrange the oxidation states.

H2 (0) + Cu (2+) O (2-) → Cu (0) + H2 (+) O (2-).

H2 (0) -2e = 2H (+) – Reducing agent (Oxidation process).

Cu (2+) + 2t = Cu (0) – Oxidizing agent (Reduction process).

d) 2Na + H2 → 2NaH.

We arrange the oxidation states.

2Na (0) + H2 (0) → 2Na (+) H (-).

Na (0) – 1e = Na (+) – Reducing agent (Oxidation process).

H2 + 2e = 2H (-) – Oxidizing agent (Reduction process).



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