Inclined with a plane of 30 degrees. The length of the slant is 4 cm. Find the length of its projection.

From point A oblique, let us lower the perpendicular AC to the plane.

The distance from the base of the inclined, point B to point C is the desired projection of the inclined onto the plane.

Triangle ABC is rectangular, then Cos ABC = BC / AB.

BC = AB * Cos ABC = 4 * Cos30 = 4 * √3 / 2 = 2 * √3 cm.

Answer: The length of the oblique projection is 2 * √3 cm.



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