Indicate any three numbers proportional to the numbers 3, 5 and 7.

First, let’s write down the general view of all sets of three numbers proportional to the numbers 3, 5 and 7.

Let a denote one third of the smallest number of such a triplet of numbers.

Since these three numbers must be proportional to the numbers 3, 5 and 7, then the smallest number of these three numbers must be equal to 3a, and the other two numbers must be equal to 5a and 7a, respectively.

Therefore, the general view of a set of three numbers proportional to the numbers 3, 5 and 7 is 3a, 5a and 7a, where a is some integer.

Choosing different values ​​for the parameter a, we get different sets of three numbers, proportional to the numbers 3, 5 and 7.

For example, with a = 5 we get 3 * 5 = 15, 5 * 5 = 25, 7 * 5 = 35.

Answer: 15, 25 and 35.



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