Indicate how much heat must be spent for the complete evaporation of 200 g of water taken at the boiling point?
| September 2, 2021 | education
Given:
m1 = 200 grams = 0.2 kilograms is the mass of water;
q = 2258 kJ / kg = 2.258 * 10 ^ 6 J / kg is the specific heat of vaporization of water.
It is required to determine the amount of heat Q (Joule) required for the complete evaporation of water of mass m1.
Q = m1 * q = 0.2 * 2.258 * 10 ^ 6 = 0.4516 * 10 ^ 6 Joules = 451.6 kJ.
Answer: for the complete evaporation of water, it is necessary to expend energy equal to 451.6 kJ.
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