Indicate the mass of the sediment resulting from the fusion of a sodium hydroxide solution weighing 200 g

| January 27, 2021 | education

Indicate the mass of the sediment resulting from the fusion of a sodium hydroxide solution weighing 200 g with a mass fraction of alkali of 6% and a solution of ferrum (II) sulfate weighing 100 g with a mass fraction of salt of 15.2%.

2NaOH + FeSO4 = Na2SO4 + Fe (OH) 2 (in this case the precipitate will be iron hydroxide).
1) Find the mass of the sodium hydroxide solute: 6 = (x / 200) * 100%. x = 12g.
2) Find the mass of the solute of ferrous sulfate: 15.2 = (y / 100) * 100%. y = 15.2g.
3) Find the amount of sodium hydroxide substance: 12 / (23 + 16 + 1) = 12/40 = 0.3 mol.
4) Find the amount of ferrous sulfate substance: 15.2 / (56 + 32 + 64) = 15.2 / 152 = 0.1 mol.
Lack of ferrous sulfate. Further calculation will be carried out due to the disadvantage.
5) Using the equation, we determine that the amount of ferrous sulfate substance is equal to the amount of ferrous hydroxide substance and is equal to 0.1 mol.
6) Find the mass of the sediment: 0.1 * (56 + 32 + 2) = 0.1 * 90 = 0.9 g – the answer.



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