Indicate the mass of water formed from 5 g of hydrogen and 40 g of oxygen.

O2 + 2H2 = 2H2O
n (H2) = m / M = 5/2 = 2.5 mol
n (O2) = 40/32 = 1.25 – there is no excess or lack
n (H2O) = 2.5 mol; m (H2o) = 2.5 * 18 = 45g
the answer is 45 grams



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