Indicate the oxidation state in the compounds: FeCl2, CO2, K2S, PCL3, NaNO3, NaNO5

Indicate the oxidation state in the compounds: FeCl2, CO2, K2S, PCL3, NaNO3, NaNO5 Make up the redox reactions H2 + S = H2S Cu + J2 = CuJ

a) FeCl2 – for Fe (+2), for Cl (-1); CO2 – at C (+4), at O (-2); K2S – for K (+1), for S (-2); PCl3 – for P (+3), for Cl (-1); NaNO3 – for Na (+1), for N (+5), for O (-2); NaNO5 – the formula is incorrectly written, because sodium always has (+1), oxygen (-2), nitrogen cannot have an oxidation state (+9). b) H2 + S = H2S. H had an oxidation state (0), became (+1), S had (0), became (-2), so H gave up one electron, but the molecule is diatomic, so we multiply by 2, S took two electrons. Least common multiple of 2, hence the coefficients in front of H and S are 1. The next reaction is the same.