Indicate the reaction products and equalize the reaction by the method of electrical balance SO2 + O2

Let’s write the initial scheme of the chemical equation:
SO2 + O2 = SO3
Let us write down the oxidation states of the elements that change it, as well as the electronic processes:
S (+4) O2 + O2 (0) = S (+6) O3 (2-)
S (+4) – 2e- = S (+6) => 2 – oxidation (S – reducing agent)
O2 (0) + 4e- = 2O (2-) => 1 – reduction (O – oxidizing agent)
Let’s arrange the coefficients in the scheme of the chemical equation using the above electronic processes:
2SO2 + O2 = 2SO3
Let’s check the correctness of the equation for the number of oxygen atoms: 6 in reagents, 6 in the product