# Inorganic substance A has the following composition: sodium – 27.38%, hydrogen – 1.19%, carbon – 14.29%, oxygen – 57.14%.

Inorganic substance A has the following composition: sodium – 27.38%, hydrogen – 1.19%, carbon – 14.29%, oxygen – 57.14%. This material was treated with an excess of hydrochloric acid to give gas B. When gas B was passed over red-hot magnesium, a white solid was formed. Its formula?

Answer: A – NaHCO3; B – CO2.
Explanation of the solution to the problem: first you need to find the molecular formula of substance A, for this we divide the mass composition of the components by the corresponding molar mass of the element:
Na: H: C: O = 27.38 / 23: 1.19 / 1: 14.29 / 12: 57.14 / 16 = 1.19: 1.19: 1.19: 3.57 = 1: 1: 13
Thus, the formula of substance A is NaHCO3.
Next, we write the reaction of interaction A with HCl:
NaHCO3 + HCl = NaCl + H2O + CO2;
CO2 – gas B.
Calcining magnesium: 2Mg + O2 = 2MgO;
Gas transmission B: MgO + CO2 = MgCO3

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