Internal one-sided angles for parallel straight lines are 48 ° and 132 °. Find the angle between the bisectors
| July 17, 2021 | education
Internal one-sided angles for parallel straight lines are 48 ° and 132 °. Find the angle between the bisectors of these angles.
Since the segment AC is the bisector of the angle BAM, the angle BAC = BAM / 2 = 132/2 = 66.
The segment BD is the bisector of the angle ABK, then the angle ABD = ABK / 2 = 48/2 = 24.
In the triangle AOB, we define the angle AOB.
Angle AOB = (180 – OAB – OBA) = (180 – 66 – 24) = 90.
Answer: The angle between the bisectors of the angles is 90.
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