Iron and aluminum parts have the same volume. Find the masses of these parts if the mass of the iron part is 12.75 g

| January 12, 2021 | education

Iron and aluminum parts have the same volume. Find the masses of these parts if the mass of the iron part is 12.75 g more than the mass of the aluminum one. The density of iron is 7800kg / m3, and the density of aluminum is 2700kg / m3.

Data: Δm (difference in mass of parts) = 12.75 g = 12.75 * 10 ^ -3 kg, V1 (volume of an iron part) = V2 (volume of an aluminum part).
Reference values: by condition ρ1 (density of iron) = 7800 kg / m3; ρ2 (density of aluminum) = 2700 kg / m3.
1) Determine the volume of parts: ρ1 * V – ρ2 * V = Δm.
(7800 – 2700) * V = 12.75 * 10 ^ -3.
V = 12.75 * 10 ^ -3 / 5100 = 2.5 * 10 ^ -6 m3.
2) Determine the masses of the parts: m1 = ρ1 * V = 7800 * 2.5 * 10 ^ -6 = 0.0195 kg = 19.5 g.
m2 = ρ2 * V = 2700 * 2.5 * 10 ^ -6 = 0.00675 kg = 6.75 g.



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