Iron filings were added to a solution containing 27 g of copper chloride. How much copper is released as a result of this reaction?

Given:
m in islands (CuCl2) = 27 g
To find:
m (Cu)
Decision:
CuCl2 + Fe = FeCl2 + Cu
n (CuCl2) = m / M = 27 g / 135 g / mol = 0.2 mol
n (CuCl2): n (Cu) = 1: 1
n (Cu) = 0.2 mol
m (Cu) = n * M = 0.2 mol * 64 g / mol = 12.8 g
Answer: 12.8 g



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