Iron is obtained by reducing iron with coal. The reaction product yield is 75%.

Iron is obtained by reducing iron with coal. The reaction product yield is 75%. Calculate how much iron can be obtained from ferric iron oxide weighing 1 ton.

Let’s make the equation:
2Fe2O3 + 3C = 4Fe + 3CO2 – ОВР, iron obtained;
M (Fe2O3) = 215.4 g / mol;
M (Fe) = 55.8 g / mol;
Let us determine the amount of moles of iron oxide, if its mass is known:
Y (Fe2O3) = m / M = 1000 / 215.4 = 4.64 mol;
Let’s make the proportion:
4.64 mol (Fe2O3) – X mol (Fe);
-2 mol -4 mol from here, X mol (Fe) = 4.64 * 4/2 = 9.28 mol;
Let’s calculate the theoretical mass of iron:
m (theoretical) = Y * M = 9.28 * 55.8 = 517.82 g.
Let us determine the practical mass of iron, taking into account the product yield of 75%:
W = m (Practical) / m (Theoretical) * 100;
m (Practice) = 517.82 * 0.75 = 388.36 g.
Answer: the mass of iron is 388.36 g.



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