Iron is produced by reduction of iron (3) oxide with coal. The yield of the reaction product is 75%

Iron is produced by reduction of iron (3) oxide with coal. The yield of the reaction product is 75%. Calculate what mass of iron can be obtained on iron oxide (3) weighing 1 ton.

Let’s write down the reaction equations:
2Fe2O3 + 3C = 3Co2 + 4 Fe.
m (Fe2O3) = 1 t = 1,000,000 g
According to the reaction equation, we see that:
ν (Fe2O3) / 2 = ν (Fe) / 4.
m (Fe2O3) / (2 * M (Fe2O3)) = m (Fe) / (4 * M (Fe)).
Let’s define the molar masses:
M (Fe2O3) = 56 * 2 + 16 * 3 = 160 g / mol.
M (Fe) = 56 g / mol.
Let us determine the mass of iron, which theoretically should be released during the reaction:
m (Fe) = m (Fe2O3) * 4 * M (Fe) / (2 * M (Fe2O3)).
Let’s substitute the numerical values:
m (Fe) = m (Fe2O3) * 4 * M (Fe) / (2 * M (Fe2O3)) = 1,000,000 * 4 * 56 / (2 * 160) = 700,000 g.
Now we will find a practical output of the metal:
Let’s make the proportion: 700,000 – 100%, x-75%.
x = 700,000 * 75/100 = 525,000 g.
Answer: 525000 g or 525 kg can be obtained. gland.