Iron is produced by reduction of iron (III) oxide with coal. The reaction product yield is 75%.
Iron is produced by reduction of iron (III) oxide with coal. The reaction product yield is 75%. Calculate what mass of iron can be obtained from iron oxide with a mass of 1 ton.
Let’s find the amount of the substance Fe2O3.
M (Fe2O3) = 160 kg / kmol.
n = 1000 kg: 160 kg / kmol = 6.25 kmol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Fe2O3 + 3C = 2Fe + 3CO
There is 2 mol of Fe per 1 mol of Fe2O3. Substances are in quantitative ratios 1: 2. The amount of Fe substance is 2 times more than Fe2O3.
n (Fe) = 2n (Fe2O3) = 6.25 kmol × 2 = 12.5 kmol.
Let us find the mass of Fe.
M (Fe) = 56 kg / kmol.
m = n × M.
m = 56 kg / kmol × 12.5 kmol = 700 kg.
We got 700 kg according to theory. The product yield according to the condition of the problem is 75%.
700 kg – 100%,
x – 75%,
x = (700 kg × 75%): 100% = 525 kg.
Answer: 525 kg.