Iron ore contains iron and impurities in a ratio of 7: 2. Find the number of tons of iron

Iron ore contains iron and impurities in a ratio of 7: 2. Find the number of tons of iron that will be obtained from 198 tons of ore?

Since the ratio of iron and impurities is 7: 2, we denote the ratio of the ratio as x, that is, 7x is the amount of iron, and 2x is the amount of impurities.

Let’s make the equation:

7x + 2x = 198;

9x = 198;

x = 198: 9 = 22.

This means that the amount of iron in the ore is 7x = 7 * 22 = 154 (t).

Answer: 198 tons of iron ore contains 154 tons of iron.