Iron reacts with dilute nitric acid to form iron (III) nitrate, nitric oxide (II), and water.

Iron reacts with dilute nitric acid to form iron (III) nitrate, nitric oxide (II), and water. Write the equation for this reaction and make an electronic balance.

A chemical reaction takes place between substances such as iron and nitric acid. As a result of the reaction, substances are formed: trivalent iron nitrate salt, bivalent nitric oxide and water. The molecular equation of the reaction can be written as follows:

Fe + 4 HNO3 = Fe (NO3) 3 + NO + 2 H2O

In order to equalize this chemical reaction, we need to put the number 4 in front of the nitric acid, and in the reaction products, put the number 2 in front of the water.
We compose the equation of electronic balance:

N 5+ + 3 e = N 2+ oxidizing agent, hence the reduction process

Fe 0 – 3 e = Fe 3+ reducing agent, hence the oxidation process.



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