Iron sheets are loaded into a car with a carrying capacity of 3 tons. how many sheets can be loaded

Iron sheets are loaded into a car with a carrying capacity of 3 tons. how many sheets can be loaded if each sheet is 2.5 m long, 120 cm wide, 2 ml thick, iron density 7800 kg * m3.

Given: M (carrying capacity of the vehicle used) = 3 t (in the SI system M = 3000 kg); L (length of each iron sheet) = 2.5m; B (sheet width) = 120 cm (SI B = 1.2 m); h (thickness) = 2 mm (in SI h = 2 * 10-3 m).

Constants: by condition ρzh (iron density) = 7800 kg / m3.

The number of sheets of iron that can be loaded by the used car is determined by the formula: N = M / m = M / (ρzh * V) = M / (ρzh * L * B * h).

Calculation: N = 3000 / (7800 * 2.5 * 1.2 * 2 * 10-3) = 64.1 (64 sheets).