Iron sulfite (II) weighing 17.6 g was treated with hydrochloric acid. Calculate the volume of hydrogen sulfide released.

Let’s make the equation:
FeS + 2HCl = FeCl2 + H2S
Let’s make the proportion:
88 — 22.4
17.6 — x
x = 17.6 * 22.4 / 88 = 4.48 l
Answer: volume 4.48 liters

 



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