Iron was added to 160 kg of copper sulfate (2). What mass of honey was released
August 30, 2021 | education|
Iron was added to 160 kg of copper sulfate (2). What mass of honey was released if the yield of the reaction product was 90% of the theoretically possible?
Based on the data, we will compose the process equation:
CuSO4 + Fe = Cu + FeSO4 – ORP, copper is released;
We make calculations:
M (CuSO4) = 159.5 g / mol;
M (Cu) = 63.5 g / mol;
m (CuSO4) = 160000 g
Determine the amount of the original substance:
Y (CuSO4) = m / M = 160000 / 159.5 = 1003 mol;
Y (Cu) = 1003 mol since the amount of substances is 1 mol.
We find the mass of the metal, taking into account the output:
m (Cu) = Y * M = 1003 * 63.5 = 63690.05 g (theoretical weight);
m (Cu) = 0.90 * 63690.5 = 57321.5 g = 57 kg 32 g
Answer: received copper weighing 57 kg 32 g
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