Iron was added to 160 kg of copper sulfate (2). What mass of honey was released

Iron was added to 160 kg of copper sulfate (2). What mass of honey was released if the yield of the reaction product was 90% of the theoretically possible?

Based on the data, we will compose the process equation:
CuSO4 + Fe = Cu + FeSO4 – ORP, copper is released;

We make calculations:
M (CuSO4) = 159.5 g / mol;

M (Cu) = 63.5 g / mol;

m (CuSO4) = 160000 g

Determine the amount of the original substance:
Y (CuSO4) = m / M = 160000 / 159.5 = 1003 mol;

Y (Cu) = 1003 mol since the amount of substances is 1 mol.

We find the mass of the metal, taking into account the output:
m (Cu) = Y * M = 1003 * 63.5 = 63690.05 g (theoretical weight);

m (Cu) = 0.90 * 63690.5 = 57321.5 g = 57 kg 32 g

Answer: received copper weighing 57 kg 32 g