Iron weighing 1.12 g completely reacted with the copper (II) sulfate solution.
| July 17, 2021 | education
Iron weighing 1.12 g completely reacted with the copper (II) sulfate solution. Find the mass of the copper precipitate formed. What amount of iron (II) sulfate was obtained?
Decision:
1) Fe + CuSO₄ = FeSO₄ + Cu
2) n (Fe) = 1.12 / 56 = 0.02 mol
3) at ur. (Fe) = n (Cu) = n (FeSO₄) = 0.02 mol
4) n (Cu) 0.02 * 64 = 1.28 g Cu sediment
Answer: 1.28g, 0.02 mol
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