Iron weighing 4.2 g reacts with an excess of chlorine. Calculate the mass of the salt obtained.

To solve the problem, we write the equation:
m = 4.2 g. X g -?
1. 2Fe + 3Cl2 = 2FeCl3 – compounds, ferric chloride (3) is released;
2. Calculations by formulas:
M (Fe) = 55.8 g / mol.
M (FeCl3) = 162.3 g / mol.
3. Determine the amount of metal Fe:
Y (Fe) = m / M = 4.2 / 55.8 = 0.075 mol;
Y (FeCl3) = 0.075 mol since the amount of substances is 1 mol according to the equation.
4. Find the mass of salt:
m (FeCl3) = Y * M = 0.075 * 162.3 = 12.17 g.
Answer: Ferric chloride was obtained weighing 12.17 g.