Is 3.2g oxygen enough to completely oxidize 2.8g iron?

Given:
m (O2) = 3.2 g
m (Fe) = 2.8 g

Find:
m required (O2) -?

Solution:
1) Write the equation of a chemical reaction:
3O2 + 4Fe => 2Fe2O3;
2) Calculate the amount of the substance Fe:
n (Fe) = m (Fe) / M (Fe) = 2.8 / 56 = 0.05 mol;
3) Determine the required amount of O2 substance:
n required (O2) = n (Fe) * 3/4 = 0.05 * 3/4 = 0.0375 mol;
4) Calculate the required mass of O2:
m required (O2) = n required (O2) * M (O2) = 0.0375 * 32 = 1.2 g;
5) Compare the given mass of O2 with the required one:
m (O2)> m required (O2).

Answer: It will be enough.