Is 57.85 ml of 22% sulfuric acid solution (density 1.155 g / ml) enough to completely dissolve 11.05

Is 57.85 ml of 22% sulfuric acid solution (density 1.155 g / ml) enough to completely dissolve 11.05 g of zinc? How much hydrogen will be released during this reaction

Given:
V solution (H2SO4) = 57.85 ml
ω (H2SO4) = 22%
ρ solution (H2SO4) = 1.155 g / ml
m (Zn) = 11.05 g

To find:
V (H2) -?

Solution:
1) H2SO4 + Zn => ZnSO4 + H2 ↑;
2) m solution (H2SO4) = ρ solution (H2SO4) * V solution (H2SO4) = 1.155 * 57.85 = 66.8168 g;
3) m (H2SO4) = ω (H2SO4) * m solution (H2SO4) / 100% = 22% * 66.8168 / 100% = 14.6997 g;
4) n (H2SO4) = m (H2SO4) / M (H2SO4) = 14.6997 / 98 = 0.15 mol;
5) n (Zn) = m (Zn) / M (Zn) = 11.05 / 65 = 0.17 mol;
6) n (H2SO4) <n (Zn);
7) n (H2) = n (H2SO4) = 0.15 mol;
8) V (H2) = n (H2) * Vm = 0.15 * 22.4 = 3.36 l.

Answer: H2SO4 is not enough; the volume of H2 is 3.36 liters.