Is there enough oxygen in a volume of 2 liters for complete combustion of 1 g of phosphorus?

Reaction of complete combustion of phosphorus 4P + 5O2 = 2P2O5
The amount of oxygen substance with a volume of 2 liters: n = V / Vm = 2l / 22.4l / mol = 0.089 mol. By reaction with 4 mol of phosphorus, 5 mol of oxygen reacts n (P) / 4 = 0.089 / 5. n (P) = 4 * 0.089 / 5 = 0.0712 mol. The mass of phosphorus is m = n * M = 0.0712 mol * 31 g / mol = 2.2 g. It turns out that 2 liters of oxygen can burn 2.2 g of phosphorus, which means that for 1 g of phosphorus this volume of oxygen is enough and even more, than necessary.