Is there enough solution with a mass of 200 g with a mass fraction of sulfuric acid of 0.2 to completely neutralize

Is there enough solution with a mass of 200 g with a mass fraction of sulfuric acid of 0.2 to completely neutralize a solution with a mass of 200 g with a mass fraction of sodium hydroxide equal to 0.3?

Given:
m solution (H2SO4) = 200 g
ω (H2SO4) = 0.2
m solution (NaOH) = 200 g
ω (NaOH) = 0.3

To find:
m solution (H2SO4) – enough?

Decision:
1) H2SO4 + 2NaOH => Na2SO4 + 2H2O;
2) m (H2SO4) = ω (H2SO4) * m solution (H2SO4) = 0.2 * 200 = 40 g;
3) n (H2SO4) = m (H2SO4) / M (H2SO4) = 40/98 = 0.41 mol;
4) m (NaOH) = ω (NaOH) * m solution (NaOH) = 0.3 * 200 = 60 g;
5) n (NaOH) = m (NaOH) / M (NaOH) = 60/40 = 1.5 mol;
6) n must. (H2SO4) = n (NaOH) / 2 = 1.5 / 2 = 0.75 mol;
7) n (H2SO4) <n should (H2SO4).

Answer: H2SO4 is not enough.