It is known that a load weighing ten kilograms falls from a certain height and reaches the surface of the earth in 5 seconds.

It is known that a load weighing ten kilograms falls from a certain height and reaches the surface of the earth in 5 seconds. It is necessary to determine the work of gravity.

Given:

m = 10 kilograms is the mass of a load freely falling from a certain height;

g = 10 m / s ^ 2 – acceleration of gravity;

t = 5 seconds – the period of time during which the cargo reaches the surface of the earth.

It is required to determine A (Joule) – the work of gravity.

The force of gravity acting on the load will be equal to:

G = m * g = 10 * 10 = 100 Newtons.

The distance that the load will travel in 5 seconds of free fall is:

S = g * t ^ 2/2 = 10 * 5 ^ 2/2 = 5 * 5 ^ 2 = 5 * 25 = 125 meters.

Then the work of gravity will be equal to:

A = F * S = 100 * 125 = 12500 Joules = 12.5 kJ.

Answer: the work of gravity will be equal to 12.5 kJ.