It is known that the slope of the line y = kx + b is -12 and this line passes through the point E (2; -20)

It is known that the slope of the line y = kx + b is -12 and this line passes through the point E (2; -20). Find the coefficients k and b.

The equation of the straight line has the form y = kx + b, where k is the slope, and at is the point of intersection of the y-axis.

1. Our straight line has a slope – 12, which means that the equation of the straight line will have the form

y = – 12x + b

2. The straight line passes through the point E (2; – 20). The x value at this point is 2 and y = – 20.

3. Substitute the values of x and y in the equation of the line and calculate the value of b.

– 20 = – 12 * 2 + b

– 20 = – 24 + b

b = – 20 + 24 = 4

4. Hence, k = -12, b = 4. The equation of the straight line will have the form y = – 12x + 4



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