It is necessary to find the average kinetic energy of a molecule of a monatomic gas

It is necessary to find the average kinetic energy of a molecule of a monatomic gas at a pressure of 300 kPa. The concentration of molecules is 4 * 10 ^ 23 m3

These tasks: monatomic gas; P (gas pressure) = 300 kPa (300 * 10 ^ 3 Pa); n (concentration of molecules) = 4 * 10 ^ 23 m-3.

We express the average kinetic energy of a molecule of a given monatomic gas from the formula: P = 2/3 * n * Ek and Ek = 3P / 2n.

Let’s calculate: Ek = 3 * 300 * 10 ^ 3 / (2 * 4 * 10 ^ 23) = 112.5 * 10 ^ -20 J = 1125 ZJ.

Answer: A molecule of a given monatomic gas has an average kinetic energy of 1125 sJ.