It is necessary to prepare 700 cm3 of a solution with a molar concentration of NaF of 2 mol / dm3.

It is necessary to prepare 700 cm3 of a solution with a molar concentration of NaF of 2 mol / dm3. How much sodium fluoride is required.

For 700 ml, you need to take 2 * 0.7 = 1.4 mol of the substance.
M NaF = 42 g / mol, mass:
42 * 1.4 = 58.8 g of sodium fluoride.



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