It is required to obtain 2000 g of a 2% fructose solution from 10%. What volume of H2O

It is required to obtain 2000 g of a 2% fructose solution from 10%. What volume of H2O and what mass of a 10% solution do you need to take for this?

Given:
m2 solution (fructose) = 2000 g
ω2 (fructose) = 2%
ω1 (fructose) = 10%

To find:
m (water) -?
m1 solution (fructose) -?

Decision:
1) m2 (fructose) = ω2 (fructose) * m2 solution (fructose) / 100% = 2% * 2000/100% = 40 g;
2) m1 (fructose) = m2 (fructose) = 40 g;
3) m1 solution (fructose) = m1 (fructose) * 100% / ω1 (fructose) = 40 * 100% / 10% = 400 g;
4) m (water) = m2 (fructose) – m1 (fructose) = 2000 – 400 = 1600 g.

Answer: The mass of water is 1600 g; the mass of the initial fructose solution is 400 g.