It takes an hour to travel by motorboat from berth x to berth y, and the return journey takes three hours

It takes an hour to travel by motorboat from berth x to berth y, and the return journey takes three hours. The speed of the boat relative to the water remains constant, how many times this speed is greater than the speed of the current

Boat speed relative to water – Vl.
Current speed – Vt.
Distance between berths x b y –S.
The time it took the boat to sail from x to y: t1 = S / (Vt + Vl).
Time for the return journey: t2 = S / (Vl-Vt).
By hypothesis, t2 / t1 = 3.
(S / (Vl-Vv)) / (S / (Vt + Vl)) = 3;
(Vl-Vt) / (Vt + Vl) = 3;
(Vl-Vt) = 3 / (Vt + Vl);
Vt + Vl = 3 * (Vl-Vt);
Vt + Vl = 3 * Vl-3 * Vt;
4 * Vt = 2 * Vl;
Vl = 2 * Vt.
Answer: The speed of the boat relative to the water is twice the speed of the current.