It took 1400 J of energy to heat a lead ball by 20 degrees C. What is the mass of the ball?

Initial data: Δt (specified change in the temperature of the lead ball) = 20 ºС; Q (amount of consumed thermal energy) = 1400 J.

Reference values: С (specific heat capacity of lead) = 140 J / (kg * ºС).

We express the mass of the taken lead ball from the formula: Q = C * m * Δt, whence m = Q / (C * Δt).

Calculation: m = 1400 / (140 * 20) = 0.5 kg (500 g).

Answer: The lead ball has a mass of 500 grams.



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