It took 180,000 energy to evaporate the alcohol at the boiling point. What is the mass of the evaporated alcohol?
February 26, 2021 | education
| It took 180,000 energy to evaporate the alcohol at the boiling point. What is the mass of the evaporated alcohol? The specific heat of vaporization of alcohol is 0.9 MJ / kg.
Problem data: Q (energy required to evaporate alcohol) = 180,000 J.
Constants: according to the condition L (specific heat of vaporization of alcohol) = 0.9 MJ / kg = 0.9 * 10 ^ 6 J / kg.
To determine the mass of the evaporated alcohol, we use the formula: Q = L * m, whence m = Q / L.
Let’s make the calculation: m = 180,000 / (0.9 * 10 ^ 6) = 0.2 kg or 200 g.
Answer: The mass of the evaporated alcohol is 200 grams.
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