It took 180,000 energy to evaporate the alcohol at the boiling point. What is the mass of the evaporated alcohol?

It took 180,000 energy to evaporate the alcohol at the boiling point. What is the mass of the evaporated alcohol? The specific heat of vaporization of alcohol is 0.9 MJ / kg.

Problem data: Q (energy required to evaporate alcohol) = 180,000 J.

Constants: according to the condition L (specific heat of vaporization of alcohol) = 0.9 MJ / kg = 0.9 * 10 ^ 6 J / kg.

To determine the mass of the evaporated alcohol, we use the formula: Q = L * m, whence m = Q / L.

Let’s make the calculation: m = 180,000 / (0.9 * 10 ^ 6) = 0.2 kg or 200 g.

Answer: The mass of the evaporated alcohol is 200 grams.



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