It was found that when a piece of copper is completely immersed in kerosene, its weight decreases by 250 N

| February 2, 2021 | education

It was found that when a piece of copper is completely immersed in kerosene, its weight decreases by 250 N. What is the volume of this piece of copper?

dP = 250 Newton – the value by which the weight of a piece of copper has decreased after immersion in kerosene;

ro = 800 kilograms / cubic meter is the density of kerosene;

g = 9.8 Newton / kilogram – acceleration of gravity.

It is required to determine V (cubic meter) – the volume of a piece of copper that is immersed in kerosene.

When a body is immersed in a liquid, its weight decreases by an amount equal to the Archimedean (buoyancy) force acting on this body. Based on this, we get that:

Farchimedes = dP = ro * g * V, from here we find:

V = dP / (ro * g) = 250 / (9.8 * 800) = 250/7840 = 25/784 = 0.032 m3 (the result has been rounded to one thousandth).

Answer: The volume of a piece of copper is 0.032 m3 (32 liters).



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