KOH was treated with a solution containing H2SO4 weighing 235 g. Determine the mass of the salt that was formed

univerkov | December 8, 2020 | education

KOH was treated with a solution containing H2SO4 weighing 235 g. Determine the mass of the salt that was formed, there is a mass fraction of the yield of 90%.

v (H2SO4) = 235 grams / 98 grams / mol = 2.4 mol;
2 KOH + H2SO4 = K2SO4 + 2 H2 O
theoretical mass (К2SO4) = 2.4 grams * 174 grams / mol = 417.6 grams
practical weight (К2SO4) = 417.6 grams * 90% / 100% = 375.84 grams

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