Lead block weighing 1.5 kg. has a length of 10 cm and a width of 6 cm. What is its thickness?

The volume of a lead block can be calculated using the formula:
V = m / ρ, where V is the required volume of the lead bar, m is the mass of the lead bar (m = 1.5 kg), ρ is the density of the lead (ρ = 11300 kg / m³).
V = a * b * c, where a is the length of the lead bar (a = 10 cm = 0.1 m), b is the width of the lead bar (b = 6 cm = 0.06 m), c is the thickness of the lead bar.
a * b * c = m / ρ.
Let us express and calculate the thickness of the lead bar:
c = m / (ρ * a * b) = 1.5 / (11300 * 0.1 * 0.06) = 0.0221 m = 2.21 cm.
Answer: The thickness of the lead bar is 2.21 cm.