Lever right shoulder 12cm, left arm 6cm. What force should act on the left arm of the lever for balance if a force of 2 N acts on the right arm?
l1 = 12 centimeters – the length of the right arm of the lever;
l2 = 6 centimeters – the length of the left arm of the lever;
F1 = 2 Newton – the force that acts on the right arm of the lever.
It is required to determine F2 (Newton) – the force that must act on the left shoulder in order for the lever to be in balance.
We translate the units of measurement of length into the SI system:
l1 = 12 cm = 12/100 = 0.12 meters.
l2 = 6 cm = 6/100 = 0.06 meters.
Since the condition of the problem is not specified, we consider the lever itself to be weightless. Then, according to the leverage rule, we get:
F1 * l1 = F2 * l2;
F2 = F1 * l1 / l2;
F2 = 2 * 0.12 / 0.06 = 0.24 / 0.06 = 4 Newtons.
Answer: a force equal to 4 Newtons must act on the left arm of the lever.
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