Lifting capacity of the elevator is 7t. how many sheets of iron can be loaded into the elevator if the length

Lifting capacity of the elevator is 7t. how many sheets of iron can be loaded into the elevator if the length of each is 2.5 m. the width is 80 cm. thickness 4 mm.

Data: M (lift capacity) = 7 t; a (sheet length) = 2.5 m; b (sheet width) = 80 cm; s (sheet thickness) = 4 mm.

Reference data: ρ (density of iron) = 7800 kg / m ^ 3.

SI system: M = 7 t = 7 * 10 ^ 3 kg; b = 80 cm = 0.8 m; s = 4 mm = 4 * 10 ^ 3 m.

1) The volume of one sheet of iron: V = a * b * s = 2.5 * 0.8 * 4 * 10 ^ -3 = 8 * 10 ^ -3 m ^ 3.

2) Weight of one sheet: m = ρ * V = 7800 * 8 * 10 ^ -3 = 62.4 kg.

3) Number of sheets that can be loaded into the elevator: n = M / m = 7 * 10 ^ 3 / 62.4 = 112 sheets of iron.